Web5 boys and 5 girls are sitting in a row randomly. The probability that boys and girls sit alternately is A 1261 B 421 C 1264 D 1266 Easy Solution Verified by Toppr Correct option is A) Total number of ways =10! Total number of ways in which 5 boys and 5 girls are sitting in a row =2×5!×5! ∴ Required probability WebThe arragement of sitting of 5 Boys and 5 Girls alternatively in a row may start with either a Boy or a Girl. So 2 types of starting are possible. Type I → BGBGBGBGBG Typy II → …
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WebExplanation: There can 5 girls selected for the first seat. Then, there are 4 girls to select from for the second seat. Then, there are 3 girls to select from for the third seat. Then, … WebQuestion 5 boys & 3 girls are sitting in a row of 8 seats. Number of ways in which they can be seated so that not all the girls sit side by side, is? A 36000 B 9080 C 3960 D 11600 Medium Solution Verified by Toppr Correct option is A) Total no of ways they can be arranged is without any restrictions = 8! ways.
WebMar 8, 2024 · The arragement of sitting of 5 Boys and 5 Girls alternatively in a row may start with either a Boy or a Girl. So 2 types of starting are possible. Type I → BGBGBGBGBG Typy II → GBGBGBGBGB In each type 5 Boys and 5 Girls may take their positions in 5! ways. So total number of possible arrangements becomes = 2 × 5! ×5! WebMar 14, 2015 · Given a particular seating arrangement of the girls, say Anne, Beth, Carol, and Dalia, the four rotations (Anne, Beth, Carol, Dalia), (Beth, Carol, Dalia, Anne), (Carol, Dalia, Anne, Beth), and (Dalia, Anne, Beth, Carol) leave the girls in the same relative order, so you must divide your answer by 4. – N. F. Taussig Mar 13, 2015 at 23:55
WebMar 2, 2024 · Answer: If the symmetry of the table is not taken into account the number of possibilities is 5! = 120. In this case it would be the same as ordering people on a line. However if rotation symmetry is taken into account, there are five ways for people to sit at the table which are just rotations of each other. So using symmetry the answer is 24. Web5 boys & 3 girls are sitting in a row of 8 seats. Number of ways in which they can be seated s... Doubtnut 2.68M subscribers Subscribe 6.6K views 4 years ago To ask …
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WebThe number of permutation of these 5 girls is 5! = 120 \color{#4257b2}{5!=120} 5! = 120. So these 5 girls can be arranged among themselfs in 120 … how much rice to make 4 cups cookedWebtrue crime, documentary film 28K views, 512 likes, 13 loves, 16 comments, 30 shares, Facebook Watch Videos from Two Wheel Garage: Snapped New Season... how do pronounce mxWeb5 boys and 5 girls sit in a row at random. The probability that the boys and girls an alternatively is A 145 B 283 C 1261 D 111 Medium Solution Verified by Toppr Correct option is C) 5 boys and 5 girls sit in a row at random ∴ No of ways they can sit =(5+5)! =10! ∴ No of ways that the boys and girls sit alternatively =51×5!×2 how do pronounce namesWebIn how many ways 5 girls and 5 boys can be seated in row such that they sit alternatively A 2×5! 2 B 10! C 5! 2 D none of these Medium Solution Verified by Toppr Correct option is A) G_ G_ G_G_ G_ _ G_ G_ G_ G_G 5 boys can be permuted in 5! ways Now for making seating arrangement 5 girls alternatively to 5 boys. 5 girls can be permuted in 5! ways. how do pronouns indicate possessionWebQuestion: (b) (5 points) In how many ways can 4 boys and 5 girls sit in a row if the boys and girls must alternate? (c) (5 points) Six digits 0, 1, 2, 3, 4, and 5 are ... how much rice water should you drinkhow do pronounce porscheWebAnswer: Let the girls be represented by R, S, Ab, M, An, as per their names and the seats by the numbers 1, 2, 3, 4, 5. We’ll try to construct their seating ... how much rice to water ratio